Question

C语言：在一个字符数组中先后存放多个字符串，是怎么存放，举例说明

Answer 1

#include <string.h>

char a[80];

//将"abcd"保存到a中
strcpy(a,"abcd");

//输出a中的字符串
puts(a);

//将"1234"保存到a中
strcpy(a,"1234);

//输出a中的字符串
puts(a);

Answer 2

#include <iostream>
using namespace std;

int main()
{
char a[80];
strcpy(a,"abcd"); //首先把abcd赋值给数组a
cout << a << endl;
strcat(a,"1234"); //把1234补加给数组a
cout << a;
system("pause");
}

Answer 3

用 strcat
char str[1024];

strcpy (str,"these ");
strcat (str,"strings ");
strcat (str,"are ");
strcat (str,"concatenated.");

str 里有
"these strings are concatenated."