因式分解:(x-y)²-x+y
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(x-y)²-x+y
= (x-y)² + (-1)x + (-1)(-y)
= (x-y)² - (x-y) (根据分配律ab+ac=a×(b+c)提出后两项里的负号)
= (x-y)(x-y) + (-1)(x-y)
= (x-y)(x-y-1) (提出x-y)
= (x-y)² + (-1)x + (-1)(-y)
= (x-y)² - (x-y) (根据分配律ab+ac=a×(b+c)提出后两项里的负号)
= (x-y)(x-y) + (-1)(x-y)
= (x-y)(x-y-1) (提出x-y)
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展开全部
(x-y)²-x+y
= (x-y)² - (x-y)
= (x-y)(x-y-1)
= (x-y)² - (x-y)
= (x-y)(x-y-1)
追问
你能把确切步骤告诉我吗?
追答
(x-y)²-x+y
= (x-y)² + (-1)x + (-1)(-y)
= (x-y)² - (x-y) (根据分配律ab+ac=a×(b+c)提出后两项里的负号)
= (x-y)(x-y) + (-1)(x-y)
= (x-y)(x-y-1) (提出x-y)
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