已知m的平方加m加3=0，求m的五次方加3m的四次方加2m的三次方加2m的二次方减10m的值
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思路：把所求里逐渐凑成m^2+m+3，然后去掉即可
m^5+3m^4+2m^3+2m^2-10m
=m^5+m^4+3m^3+2m^4-m^3+2m^2-10m
=m^3(m^2+m+3)+2m^4-m^3+2m^2-10m (m^2+m+3=0,直接去掉)
=2m^4-m^3+2m^2-10m
=2m^4+2m^3+6m^2-3m^3-4m^2-10m=-3m^3-4m^2-10m
=-3m^3-3m^2-9m-m^2-m=-m^2-m-3+3
=3
m^5+3m^4+2m^3+2m^2-10m
=m^5+m^4+3m^3+2m^4-m^3+2m^2-10m
=m^3(m^2+m+3)+2m^4-m^3+2m^2-10m (m^2+m+3=0,直接去掉)
=2m^4-m^3+2m^2-10m
=2m^4+2m^3+6m^2-3m^3-4m^2-10m=-3m^3-4m^2-10m
=-3m^3-3m^2-9m-m^2-m=-m^2-m-3+3
=3
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