已知x=2+根号3分之1，求x-1分之1-2x+x²-（x²-x分之根号x²-2x+1）的值
1个回答
展开全部
x=1/(2+√3)=2-√3
(1-2x+x²)/(x-1)-(x²-2x+1)/(x²-x)
=(x-1)²/(x-1)-(x-1)²/)x(x-1)
=(x-1)-(x-1)/x
=(x-1)(1-1/1x)
=(2-√3-1)[1-1/(2-√3)]
=(1-√3)[1-(2+√3)]
=(1-√3)[-1-√3]
=-(1-√3)(1+√3)
=-[1²-(√3)²]
=-[1-3]
=-(-2)
=2
(1-2x+x²)/(x-1)-(x²-2x+1)/(x²-x)
=(x-1)²/(x-1)-(x-1)²/)x(x-1)
=(x-1)-(x-1)/x
=(x-1)(1-1/1x)
=(2-√3-1)[1-1/(2-√3)]
=(1-√3)[1-(2+√3)]
=(1-√3)[-1-√3]
=-(1-√3)(1+√3)
=-[1²-(√3)²]
=-[1-3]
=-(-2)
=2
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
