求一个最快的C语言算素数程序
最好是1秒钟就能到10000000,但是不太可能啦。
我网上找到一个,但是不够快
#include<math.h>
void main()
{
int i,n;
printf("%d ", 2); //素数2单独输出
for(n=3; n<=99; n+=2) {
int temp=int(sqrt(n));
for(i=2; i<=temp; i++)
if(n %i == 0) break; //执行break时为非正常结束循环
if(i>temp) printf("%d ", n); //输出一个素数
}
printf("\n");
}
有的话就提供吧,越快越好,最快的我会加分的。 展开
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#define MAX 10000000
void select(_Bool *series,int num)
{
int i;
for(i=2;i*num<=MAX;i++) series[i*num] = 0;
}
main()
{
int sum=0,i;
int maxsqrt=sqrt(MAX);
_Bool *series=(_Bool*)malloc((MAX+1)*sizeof(_Bool));
for (i=0;i<=MAX;i++) series[i] = 1;
for (i=2;i<=MAX;i++)
{
if(series[i])
{
sum++;
//printf("%d\n",i);
if(i<=maxsqrt)select(series,i);
}
}
printf("\n%d以内共有%d个素数",MAX,sum);
free(series);
return 0;
}
它可以在1秒解决1000万,20秒左右解决10亿。当然实际上不同电脑会有些差异,速度的代价就是是需要申请较大的内存空间
在前面做了一些辅助算法,所以正式算法里面没有除法、乘法、求余等运算,速度快了很多
小于1000 0000找到664579个素数,用时777毫秒
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</script>
<script>
var n=parseInt(window.prompt('请输入要找的素数:'))
var s=parseInt(Math.sqrt(n))+1;
var aa;
var count;
var count1=0;
var ss=[];
var ssss=[];
var s2=[];
var sushu=[];
var bzc=true;
var k=2;
ss[0]=2;
ss[1]=2;
ssss[0]=0;
ssss[1]=4;
s2[0]=0;
s2[1]=2;
var i,j;
var myDate = new Date();
for(i=3;i<s;i+=2){
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for(j=1;(bzc&&ssss[j]<=i);j++){
if(i%ss[j]==0)bzc=false;//count++;
}
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//document.write(i+" ");
ssss[k]=i*i;
s2[k]=i<<1;
ss[k++]=i;
}
else
bzc=true;
}
for(i=1;ss[i]<s;i++){
for( j=ssss[i];j<n;j+=s2[i]){
sushu[j]=true;
}
}
aa='';
for(j=2;j<n;j++){
if( !sushu[j]){
aa+=(j+'\t');
count1++;
if(count1%10==0)
aa+=('\r\n');
}
}
//document.write(aa);
var file = new File([aa], n+"以下素数.txt", { type: "text/plain;charset=utf-8" });
saveAs(file);
var myDate2 = new Date();
document.write("找到"+(count1)+"个素数,用时"+(parseInt(myDate2 - myDate))+"毫秒");
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