Question

学长学姐，这个第六题可以给个详细步骤吗？自己求导没求出来答案。。

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Answer 1

Answer 2

z = (1+xy)^y = e^[yln(1+xy)]
∂z/∂x = e^[yln(1+xy)] [y/(1+xy)] y = [y^2/(1+xy)] (1+xy)^y,
∂z/∂y = e^[yln(1+xy)] [ln(1+xy)+yx/(1+xy)] = [ln(1+xy)+yx/(1+xy)](1+xy)^y