Question

哪位牛人帮我解一下这道一元一次方程

就是解得的那个

Answer 1

首先消敬塌，方程两边同除以U，得到：(1.2-h)/(1.2×1.2)+h/(2.4×1.2)=1/1.6

==> [1.2/(1.2×1.2)]-h/(1.2×1.2)+(1/2)×h/(1.2×1.2)=1/1.6

==> (1/1.2)-(1/2)h/(1.2×1.2)=1/1.6

==> (1/1.2)-(1/1.6)=(1/2)h/(1.2×1.2)

==> (1.6-1.2)/(1.2×1.6)=(1/2)h/(1.2×1.2)

==>拿圆 0.4/(1.2×1.6)=(1/2)h/(1.2×1.2)

==>稿纯 0.4/1.6=(1/2)h/1.2

==> 1/4=(1/2)h/1.2

==> (1/2)h=1.2×(1/4)=0.3

==> h=0.6