Question

char *a[10] = {"Fortran","Basic","pascal","C","C++"};

a[10]不是应该是指针数组么。
为什么这么写呢？
应该存放着char * 类型的呀，为什么是char类型的呢？

Answer 1

char *a[10]
[ ] 优先级高于 *
所以这是一个数组
数组的元素类型是 char *
即字符型指针，指向字符串
char *a[10] = {"Fortran","Basic","pascal","C","C++"};
a[0] = "Fortran"; a[1] = "Basic"; ...............
不是 char
如果是char
char a[3] = { 'a', 'b', '\0'};
类同 char a[3] = "ab";

追问

按照上面定义的，*a[0]是不是 "F"

追答

是的 *a[0] ,a[0][0] 都是 F
char *a[10] = {"Fortran","Basic","pascal","C","C++"};

如果这样初始化， 就不能去修改字符串。

Answer 2

char[x] 里面存的是字符串的首地址