Question

初一因式分解计算题要有过程哦 高分悬赏

6p(m+n)-4q(m+n) 3x(a+2b）�0�5-6xy(a+2b) x(x-y)�0�5+x(x+y)(y-x)+2（x-y) 11�0�5-a�0�5 9(a-b)�0�5-4(a+b)�0�5 9(2a+3b)�0�5-25(3a-b)�0�5 49（x-2)�0�5-25(x 简便计算 9999�0�5+9999 2005+2005�0�5-2006�0�5 注：我们只学过a�0�5-b�0�5=(a+b)(a-b) a�0�5+2ab+b�0�5=(a+b)�0�5 a�0�5-2ab+b�0�5=(a-b)�0�5这三种公式，一定要照这三种公式做，要步骤的 帮帮忙！

Answer 1

6p(m+n)-4q(m+n)=(m+n)(6p-4q)=2(m+n)(3p-2q) 3x(a+2b）�0�5-6xy(a+2b)=(a+2b)((3x(a+2b)-6xy)=(a+2b)(3ax+6bx-6xy)=3(a+2b)(ax+2bx-2xy) x(x-y)�0�5+x(x+y)(y-x)+2（x-y)=x(x-y)(x-y)+x(x-y)(x+y)+2(x-y)=(x-y)(x�0�5-xy+x�0�5-xy+2)=(x-y)(2x�0�5-2xy+2)=2(x-y)(x�0�5-xy+1) 11�0�5-a�0�5 =(11-a)(11+a) 9(a-b)�0�5-4(a+b)�0�5=(3a-3b)�0�5-(2a+2b)�0�5=(3a-3b+2a+2b)(3a-3b-2a-2b)=(5a-b)(a-5b)9(2a+3b)�0�5-25(3a-b)�0�5=(6a+9b)�0�5-(15a-5b)�0�5=(6a+9b+15a-5b)(6a+9b-15a+5b)=(21a+4b)(14b-9a) 49（x-2)�0�5-25(x这道题题目？ 简便计算 9999�0�5+9999=9999（9999+1）=9999*10000=99990000 2005+2005�0�5-2006�0�5=2005+2005�0�5-（2005+1）�0�5=2005（（1+2005-（2005+1））=2005*0=0

Answer 2

6p(m+n)-4q(m+n)=(m+n)（6p-4q) 3x(a+2b）�0�5-6xy(a+2b)=3x(a+2b)(a+2b-2y) x(x-y)�0�5+x(x+y)(y-x)+2（x-y)=(x-y)[x(x-y)-x(x+y)+2]=2(x-y)(1-xy) 11�0�5-a�0�5 =(11-a)(11+a) 9(a-b)�0�5-4(a+b)�0�5 =[3(a-b)-2(a+b)][3(a-b)+2(a+b)]=(a-5b)(5a-b) 9(2a+3b)�0�5-25(3a-b)�0�5 =[3(2a+3b)-5(3a-b)][3(2a+3b)+5(3a-b)]=(14b-9a) (21a+4b) 9999�0�5+9999=9999(9999+1)=9999*10000=99990000 2005+2005�0�5-2006�0�5=2005(1+2005)-2006�0�5=2005*2006-2006*2006=2006(2005-2006)=-2006

Answer 3

6p(m+n)-4q(m+n)=(6p-4q)(m+n) 3x(a+2b）�0�5-6xy(a+2b)=3x(a+2b)(a+2b-2y)x(x-y)�0�5+x(x+y)(y-x)+2（x-y)=2(x-y)(1-xy)11�0�5-a�0�5=(11+a)(11-a)9(a-b)�0�5-4(a+b)�0�5=(5a-b)(a-5b) 9(2a+3b)�0�5-25(3a-b)�0�5=(21a+4b)(14b-9a) 49（x-2)�0�5-25(x ???? 简便计算9999�0�5+9999=9999(9999+1)=99990000 2005+2005�0�5-2006�0�5=2005-(2006+2005)(2006-2005)=-2006