Question

sql查询怎么样把3个字段内容都一样的数据只显示一条？

Answer 1

查找所有重复标题的记录：
SELECT
*
FROM
t_info
a
WHERE
((SELECT
COUNT(*)
FROM
t_info
WHERE
Title
=
a.Title)
>
1)
ORDER
BY
Title
DESC
一。查找重复记录
1。查找全部重复记录
Select
*
From
表
Where
重复字段
In
(Select
重复字段
From
表
Group
By
重复字段
Having
Count(*)>1)
2。过滤重复记录(只显示一条)
Select
*
From
HZT
Where
ID
In
(Select
Max(ID)
From
HZT
Group
By
Title)
注：此处显示ID最大一条记录
二。删除重复记录
1。删除全部重复记录（慎用）
Delete
表
Where
重复字段
In
(Select
重复字段
From
表
Group
By
重复字段
Having
Count(*)>1)
2。保留一条（这个应该是大多数人所需要的
^_^）
Delete
HZT
Where
ID
Not
In
(Select
Max(ID)
From
HZT
Group
By
Title)
注：此处保留ID最大一条记录
1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断
select
*
from
people
where
peopleId
in
(select
peopleId
from
people
group
by
peopleId
having
count(peopleId)
>
1)
2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录
delete
from
people
where
peopleId
in
(select
peopleId
from
people
group
by
peopleId
having
count(peopleId)
>
1)
and
rowid
not
in
(select
min(rowid)
from
people
group
by
peopleId
having
count(peopleId
)>1)
3、查找表中多余的重复记录（多个字段）
select
*
from
vitae
a
where
(a.peopleId,a.seq)
in
(select
peopleId,seq
from
vitae
group
by
peopleId,seq
having
count(*)
>
1)
4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录
delete
from
vitae
a
where
(a.peopleId,a.seq)
in
(select
peopleId,seq
from
vitae
group
by
peopleId,seq
having
count(*)
>
1)
and
rowid
not
in
(select
min(rowid)
from
vitae
group
by
peopleId,seq
having
count(*)>1)
5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录
select
*
from
vitae
a
where
(a.peopleId,a.seq)
in
(select
peopleId,seq
from
vitae
group
by
peopleId,seq
having
count(*)
>
1)
and
rowid
not
in
(select
min(rowid)
from
vitae
group
by
peopleId,seq
having
count(*)>1)
补充：
有两个以上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复，比较容易解决，使用
select
distinct
*
from
tableName
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除
select
distinct
*
into
#Tmp
from
tableName
drop
table
tableName
select
*
into
tableName
from
#Tmp
drop
table
#Tmp
发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。
2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下
假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集
select
identity(int,1,1)
as
autoID,
*
into
#Tmp
from
tableName
select
min(autoID)
as
autoID
into
#Tmp2
from
#Tmp
group
by
Name,autoID
select
*
from
#Tmp
where
autoID
in(select
autoID
from
#tmp2)