Question

java后台怎么解析含有特殊字符的json字符串，如含有逗号，冒号等特殊字符

{"s0":413,"m1":"sdfs,123,sdf,sdfsdf,sdfsdf","m2":"","m3":"","m4":"","m5":"摘要","m6":"豫检【2002】1号字","m7":"sdfs,dfsdf,122,sss","m8":"2012-11-07","s2":"2012","s10":0,"s1":"永久","m11":"sdfsdf","m12":"李四","s7":"1","m15":"档案室","m16":"情况说明","s3":"","m19":2,"m20":"sdfs","m23":"绝密","s14":1,"s15":0,"m26":"","s5":"1","s6":"65891","s4":"m29m29m29m29m31","m29":"2012-11-09 16:36:33","m30":"2012-11-09 16:36:33","m31":0,"m32":"","s11":"0413","s12":"0413","s13":"admin","s18":"abc,123,abc,123"},像这种不确定键值的字符串怎么解析

Answer 1

这个你不需要理会，json的组装方式就是这样的，你只需要按钮普通的取值方式从它里面取就行了如：把传过的的对象当成是map的话，就int num = (Integer) map.get("s0"); //413
String m1 = map.get("m1").toString(); //"sdfs,123,sdf,sdfsdf,sdfsdf"

追问

因为我这个方法是公用的，字符串中的s1，m1等都不是确定的，也许有的字符串中有s1,而有的没有，所以不能确定get中的值

追答

那你干脆就取对象就行了，
for (Objcet o : map) {
system.out.println(o.toString());
}

追问

我的意思是我想把这个字符串中的值拆分开来，然后再放到map的集合中。但是我用逗号和冒号拆分时都会把有的值拆分成两个字符串。比如123,344这样的会变成两个了，而不是一个值

追答

你可以通过Object[] aa = {...}.split(",\""); //取得集合中的所有对象
这样每个对象中都会变成key与value 的对。 "m1":"sdfs,123,sdf,sdfsdf,sdfsdf"
接下来要怎样自己可以处理了。