Question

x-2（四分之1X-三分之一y的平方）+（-二分之三x+三分之一y的平方)其中x=二分之三，y=2，求值

Answer 1

原式=x-1/2x+2/3y^2-3/2x+1/3y^2=-x+y^2
x=3/2,y=2带入,原式=-2/3+2^2=-1/2

Answer 2

原式=x-2(x/4-y²/3)+(-3x/2+y²/3)
=x-x/2+2y²/3-3x/2+y²/3
=-x+y²
=-2/3+2²
=10/3.