各位学霸们,拜托了!!!
4个回答
2014-07-26
展开全部
用勾股定理:
AF^2 = AD^2 + DF^2 (AD=AB,DF=1/2AB)
=AB^2 + 1/4 AB^2
=5/4 AB^2
=10/16AB^2
EF^2 = CF^2 + CE^2 (CF=1/2AB,CE=1/4AB)
=1/4AB^2 + 1/16AB^2
=5/16AB^2
AE^2 = AB^2 + BE^2 (BE=3/4AB)
=AB^2 + 9/16AB^2
=25/16AB^2
AF^2 + EF^2 =25/16AB^2 = AE^2
得:AE^2 = AE^2 + EF^2
所以AF垂直EF.
AF^2 = AD^2 + DF^2 (AD=AB,DF=1/2AB)
=AB^2 + 1/4 AB^2
=5/4 AB^2
=10/16AB^2
EF^2 = CF^2 + CE^2 (CF=1/2AB,CE=1/4AB)
=1/4AB^2 + 1/16AB^2
=5/16AB^2
AE^2 = AB^2 + BE^2 (BE=3/4AB)
=AB^2 + 9/16AB^2
=25/16AB^2
AF^2 + EF^2 =25/16AB^2 = AE^2
得:AE^2 = AE^2 + EF^2
所以AF垂直EF.
追答
用勾股定理:
AF^2 = AD^2 + DF^2 (AD=AB,DF=1/2AB)
=AB^2 + 1/4 AB^2
=5/4 AB^2
=10/16AB^2
EF^2 = CF^2 + CE^2 (CF=1/2AB,CE=1/4AB)
=1/4AB^2 + 1/16AB^2
=5/16AB^2
AE^2 = AB^2 + BE^2 (BE=3/4AB)
=AB^2 + 9/16AB^2
=25/16AB^2
AF^2 + EF^2 =25/16AB^2 = AE^2
得:AE^2 = AE^2 + EF^2
所以AF垂直EF.
所以角afp是直角
用勾股定理:
AF^2 = AD^2 + DF^2 (AD=AB,DF=1/2AB)
=AB^2 + 1/4 AB^2
=5/4 AB^2
=10/16AB^2
EF^2 = CF^2 + CE^2 (CF=1/2AB,CE=1/4AB)
=1/4AB^2 + 1/16AB^2
=5/16AB^2
AE^2 = AB^2 + BE^2 (BE=3/4AB)
=AB^2 + 9/16AB^2
=25/16AB^2
AF^2 + EF^2 =25/16AB^2 = AE^2
得:AE^2 = AE^2 + EF^2
所以AF垂直EF.
所以角afe是直角
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2014-07-26
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