Question

逻辑函数表达式第三题怎么化简？

Answer 1

Y=AB' +C+A'C'D+BC'D

=AB' +(C+C'A'D) +BC'D

=AB' +C+A'D + BC'D

=AB'+A'D +C+C'BD

=AB'+A'D +C+BD

=C+AB' +A'D +BD

=C +AB' +D(A'+B)

=C+AB' + D(AB')'

=C +AB' +D

Answer 2

为方便打字，我们以小写代表非
Y=Ab+C+acD+BcD
=C+Ab*(cD)非+AbcD+acD+BcD
=C+Ab(C+d)+(Ab+a+B)cD
=C+AbC+Abd+[Ab+(Ab)非]cD
=C+Abd+cD
=C+D+Abd
=C+D+Ab