Question

java语言中编程对十个整数进行从小到大排序

Answer 1

import java.util.Scanner;

//键盘输入，冒泡排序
public class Example9_19
{ public static void main(String args[])
{ Scanner in=new Scanner(System.in);
int n=10;
int data[]=new int[n];
for(int i=0;i<data.length;i++)
{ System.out.println("请输入第"+(i+1)+"个数");
data[i]=in.nextInt();
}
System.out.print("排序前：");
for(int i=0;i<data.length;i++)
System.out.print(data[i]+" ");
bubbleSort(data);
System.out.print("\n排序后：");
for(int i=0;i<data.length;i++)
System.out.print(data[i]+" ");
}
public static void bubbleSort(int[] a)
{ //冒泡
int temp,i,j;
for(i=0;i<a.length-1;i++)
{ for(j=i+1;j<a.length;j++)
{ if(a[i]>a[j])
{ //将较小的数交换到第i个位置
temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
}

}

Answer 2

int temp = 0;
int a[] = {1,2,4,10,8,7,5,6,9,3};
for(int i=0;i<a.length-1;i++){
for(int j =i+1;j<a.length;j++) {
if(a[i]>a[j]) {
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}

Answer 3

你是不是问了for和while的问题？