Question

怎么用c#编程图中下面那几个星号那样的图形？

Answer 1

            Console.WriteLine("ShowLeftARightTriangle:\n");
            ShowLeftARightTriangle(3);
            Console.WriteLine("\nShowRightARightTriangle:\n");
            ShowRightARightTriangle(3);
            Console.WriteLine("\nShowIsoscelesTriangleo:\n");
            ShowIsoscelesTriangleo(3);
            Console.WriteLine("\nShowCurve:\n");
            ShowCurve(3);
        }
        private static void ShowLeftARightTriangle(int n)
        {
            for (int i = 1; i <= n; i++)
            {
                for (int j = 0; j < i; j++)
                {
                    Console.Write("*");
                }
                Console.Write("\n");
            }
        }
        private static void ShowRightARightTriangle(int n)
        {
            for (int i = n; i > 0; i--)
            {
                for (int j = n - i; j < n - 1; j++)
                {
                    Console.Write(" ");
                }
                for (int j = n - i + 1; j > 0; j--)
                {
                    Console.Write("*");
                }
                Console.Write("\n");
            }
        }
        private static void ShowIsoscelesTriangleo(int n)
        {
            for (int i = n; i > 0; i--)
            {
                for (int j = n - i; j < n - 1; j++)
                {
                    Console.Write(" ");
                }
                for (int j = n - i + 1; j > 0; j--)
                {
                    Console.Write("*");
                }
                for (int j = i; j < n; j++)
                {
                    Console.Write("*");
                }
                Console.Write("\n");
            }
        }
        private static void ShowCurve(int n)
        {
            for (int i = n; i > 0; i--)
            {
                for (int j = n - i; j < n - 1; j++)
                {
                    Console.Write(" ");
                }
                Console.Write("*");
                for (int j = n - i + 1; j > 1; j--)
                {
                    Console.Write(" ");
                }
                for (int j = i; j < n - 1; j++)
                {
                    Console.Write(" ");
                }
                if (i != n)
                {
                    Console.Write("*");
                }
                if (i == 1)
                {
                    for (int j = 2 * (n - 1); j > 1; j--)
                    {
                        Console.Write(" ");
                    }
                    Console.Write("*");
                }
                Console.Write("\n");
            }
            for (int i = 0; i < n - 1; i++)
            {
                for (int j = 2 * n - 1 + i; j > 0; j--)
                {
                    Console.Write(" ");
                }
                Console.Write("*");
                for (int j = 1; j < n - i - 2; j++)
                {
                    Console.Write(" ");
                }
                for (int j = n - 2; j > i; j--)
                {
                    Console.Write(" ");
                }
                if (i != n - 2)
                {
                    Console.Write("*");
                }
                Console.Write("\n");
            }
        }

Answer 2

for循环嵌套

追问

能告诉我具体怎么做吗，老师给的作业，但是我还一点也没接触过编程

谢谢