Question

java简单个一个小程序 错在哪里啊！提示少了个 “{”

abstract class Person{
private String name;
private int age;
public Person(String name,int age){
this.name = name;
this.age = age;
}
public void setName(String name){
this.name = name;
}
public void setAge(int age){
this.age = age;
}
public String getName(){
return this.name;
}
public int getAge(){
return this.age;
}
public void print();
};
class Student extends Person(){
private String school;
public Student(String name,int age,String school){
super(name,age);
this.school = school;
}
public void setSclool(String school){
this.school = school;
}
public String getSchool(){
return this.school;
}
public void print(){
System.out.println(super.getName()+","+super.getAge()+","+this.getSchool());
}
};
public class AbstractDemo02{
public static void main(String args[]){
Student stu = new Student("chengchao",24,"hefeixueyuan");
stu.print();
}
};
class Student extends Person(){ 提示的是这一行附近。

Answer 1

public void print();这是个什么，没方法体，如果想让它成为抽象方法就加abstact，如果不想就把类的抽象符给去掉，你一个抽象方法都没有，用什么抽象标识符
class Student extends Person() 你见过还能继承类的构造方法的？

Answer 2

abstract class Person{
private String name;
private int age;
public Person(String name,int age){
this.name = name;
this.age = age;
}
public void setName(String name){
this.name = name;
}
public void setAge(int age){
this.age = age;
}
public String getName(){
return this.name;
}
public int getAge(){
return this.age;
}
public abstract void print();
}
class Student extends Person{
private String school;
public Student(String name,int age,String school){
super(name,age);
this.school = school;
}
public void setSclool(String school){
this.school = school;
}
public String getSchool(){
return this.school;
}
public void print(){
System.out.println(super.getName()+","+super.getAge()+","+this.getSchool());
}
}
public class AbstractDemo02{
public static void main(String args[]){
Student stu = new Student("chengchao",24,"hefeixueyuan");
stu.print();
}
}

Answer 3

第20行少{}，改成
public void print()

{

}

Answer 4

上面是对的