Question

C# 如何获取照片中Exif信息里GPS信息与经纬度数

如题..

Answer 1

/// <summary>
/// 获取图片中的GPS坐标点
/// </summary>
/// <param name="p_图片路径">图片路径</param>
/// <returns>返回坐标【纬度+经度】用"+"分割 取数组中第0和1个位置的值</returns>
public String fnGPS坐标(String p_图片路径)
{
String s_GPS坐标 = "";
//载入图片
Image objImage = Image.FromFile(p_图片路径);
//取得所有的属性(以PropertyId做排序)
var propertyItems = objImage.PropertyItems.OrderBy(x => x.Id);
//暂定纬度N(北纬)
char chrGPSLatitudeRef = 'N';
//暂定经度为E(东经)
char chrGPSLongitudeRef = 'E';
foreach (PropertyItem objItem in propertyItems)
{
//只取Id范围为0x0000到0x001e
if (objItem.Id >= 0x0000 && objItem.Id <= 0x001e)
{
objItem.Id = 0x0002;
switch (objItem.Id)
{
case 0x0000:
var query = from tmpb in objItem.Value select tmpb.ToString();
string sreVersion = string.Join(".", query.ToArray());
break;
case 0x0001:
chrGPSLatitudeRef = BitConverter.ToChar(objItem.Value, 0);
break;
case 0x0002:
if (objItem.Value.Length == 24)
{
//degrees(将byte[0]~byte[3]转成uint, 除以byte[4]~byte[7]转成的uint)
double d = BitConverter.ToUInt32(objItem.Value, 0) * 1.0d / BitConverter.ToUInt32(objItem.Value, 4);
//minutes(将byte[8]~byte[11]转成uint, 除以byte[12]~byte[15]转成的uint)
double m = BitConverter.ToUInt32(objItem.Value, 8) * 1.0d / BitConverter.ToUInt32(objItem.Value, 12);
//seconds(将byte[16]~byte[19]转成uint, 除以byte[20]~byte[23]转成的uint)
double s = BitConverter.ToUInt32(objItem.Value, 16) * 1.0d / BitConverter.ToUInt32(objItem.Value, 20);
//计算经纬度数值, 如果是南纬, 要乘上(-1)
double dblGPSLatitude = (((s / 60 + m) / 60) + d) * (chrGPSLatitudeRef.Equals('N') ? 1 : -1);
string strLatitude = string.Format("{0:#} deg {1:#}' {2:#.00}\" {3}", d
, m, s, chrGPSLatitudeRef);
//纬度+经度
s_GPS坐标 += dblGPSLatitude + "+";
}
break;
case 0x0003:
//透过BitConverter, 将Value转成Char('E' / 'W')
//此值在后续的Longitude计算上会用到
chrGPSLongitudeRef = BitConverter.ToChar(objItem.Value, 0);
break;
case 0x0004:
if (objItem.Value.Length == 24)
{
//degrees(将byte[0]~byte[3]转成uint, 除以byte[4]~byte[7]转成的uint)
double d = BitConverter.ToUInt32(objItem.Value, 0) * 1.0d / BitConverter.ToUInt32(objItem.Value, 4);
//minutes(将byte[8]~byte[11]转成uint, 除以byte[12]~byte[15]转成的uint)
double m = BitConverter.ToUInt32(objItem.Value, 8) * 1.0d / BitConverter.ToUInt32(objItem.Value, 12);
//seconds(将byte[16]~byte[19]转成uint, 除以byte[20]~byte[23]转成的uint)
double s = BitConverter.ToUInt32(objItem.Value, 16) * 1.0d / BitConverter.ToUInt32(objItem.Value, 20);
//计算精度的数值, 如果是西经, 要乘上(-1)
double dblGPSLongitude = (((s / 60 + m) / 60) + d) * (chrGPSLongitudeRef.Equals('E') ? 1 : -1);
}
break;
case 0x0005:
string strAltitude = BitConverter.ToBoolean(objItem.Value, 0) ? "0" : "1";
break;
case 0x0006:
if (objItem.Value.Length == 8)
{
//将byte[0]~byte[3]转成uint, 除以byte[4]~byte[7]转成的uint
double dblAltitude = BitConverter.ToUInt32(objItem.Value, 0) * 1.0d / BitConverter.ToUInt32(objItem.Value, 4);
}
break;
}
}
}
return s_GPS坐标;
}
#endregion

Answer 2

http://blog.csdn.net/hefeng_aspnet/article/details/8681047

Answer 3

 刚好我也在做这个东西，用了个类库，你可以参考下

但是我搞不出来经纬度的秒，只能获取度和分分，秒获取的值总是零，希望up主解决了告诉我一声