1+1/2+1/4+1/8+1/16+1/32+1/64 奥数题，简便计算过程，/是分数线，÷是除号
1+1/2+1/4+1/8+1/16+1/32+1/64 奥数题，简便计算过程，/是分数线，÷是除号
额！可以用等比数列的前n项和公式吗？
s=(1-(1/2)^7)/(1-1/2)*1=(1/2)^6
不过似乎也不是很简单，如果你找到了也告诉我吧！
（1＋1/3）×（1＋1/9）×（1＋1/81） 奥数题，简便计算过程，/是分数线，÷是除号
（1+1/3）（1+1/9）（1+1/81）
=(1-1/3)（1+1/3）（1+1/9）（1+1/81） x3/2
=(1-1/9)（1+1/9）（1+1/81）x3/2
=(1-1/81)（1+1/81） x3/2
=(1-1/6561)x3/2
=6560/6561x3/2
=3280/2187
1/1×4＋1/4×7＋1/7×14＋…＋1/97×100 奥数题，简便计算过程，/是分数线，÷是除号
1/(1*4)+1/(4*7)+1/(7*10)+....+1/(97*100)
=1/3*(1-1/4)+1/3*(1/4-1/7)+1/3*(1/7-1/10)+....+1/3*(1/97-1/100)
=1/3*(1-1/4+1/4-1/7+1/7-1/10+......+1/97-1/100)
=1/3*(1-1/100)
=33/100
(2/2)－1/9）×（1－1/10） 奥数题，简便计算过程，/是分数线，÷是除号
是不是(1-1/2)×(1-1/3)×……×(1-1/9)×(1-1/10)
=1/2×2/3×……×8/9×9/10
前一个分母和后一个分子约分
=1/10
1/2+1/4+1/8+1/16+1/32 简算，是分数
1/2+1/4+1/8+1/16+1/32
=1-1/32
=31/32
1/2+1/4+1/8+1/16+1/32+1/64 简便运算 写出具体过程 急！给5分
1/2+1/4+1/8+1/16+1/32+1/64
=1/2+1/4+1/8+1/16+1/32+1/64+1/64-1/64
=1/2+1/4+1/8+1/16+1/32+1/32-1/64
=1/2+1/4+1/8+1/16+1/16-1/64
=1/2+1/4+1/8+1/8-1/64
=1/2+1/4+1/4-1/64
=1/2+1/2-1/64
=1-1/64
=63/64
用简便计算1+1/2+1/4+1/8+1/14+1/22+1/32+1/44+1/58+1/74
1+1/2+1/4+1/8+1/14+1/22+1/32+1/44+1/58+1/74
=2-1/8+1/32+1/（2*7）+1/（2*11）+1/（4*11）+1/（2*29）+1/（2*37）
=2+(-330484+82621+188848+120176+60088+45584+35728)/(32*7*11*29*37)
=2+202561/2643872.
用两种方法计算1/2+1/4+1/8+1/16+1/32+1/64
1、原式=32/64+16/64+8/64+4/64+2/64+1/64=63/64
2、原式=1/2+1/4+1/8+1/16+1/32+(1/64+1/64)-1/64
=1/2+1/4+1/8+1/16+(1/32+1/32)-1/64
=1/2+1/4+1/8+(1/16+1/16)-1/64
=1/2+1/4+(1/8+1/8)-1/64
=1/2+(1/4+1/4)-1/64
=(1/2+1/2)-1/64
=1-1/64
=63/64
