Question

根号6减根号2的绝对值加1减根号2的绝对值加根号6减3的绝对值是什么?

Answer 1

√6-√2﹥0,1-√2﹤0,√6-3﹤0
所以
原式=|√6-√2|+|1-√2|+|√6-3|
=√6-√2+[-(1-√2)]+[-(√6-3)]
=√6-√2+√2-1+3-√6
= -1+3
=2