
ASP 数据库问题
<%dimconnh,mdbfileh,pppppppppp=application("3gk")mdbfileh=server.mappath("3gwapkj/#ou...
<%
dim connh,mdbfileh,ppppp
ppppp=application("3gk")
mdbfileh=server.mappath("3gwapkj/#our_668.asp")
set connh=server.createobject("adodb.connection")
connh.open "driver={microsoft access driver (*.mdb)};uid=admin;pwd=;dbq="&mdbfileh
set rsh=server.createobject("adodb.recordset")
rsh.open "select url from urls where id="&ppppp&"",connh,3,2
if Not rsh.eof Then
iii=rsh("url")
response.write "<img src='"&iii&"' alt='jjjjjjjj'/><br />"
rsh.movenext
if not rsh.eof Then
uuu=rsh("url")
response.write ".....................<img src='"&uuu&"' alt='jlllllllhgg'/><br />"
Else
ppppp=0
end if
Else
ppppp=0
end if
rsh.close
set rsh=nothing
connh.close
set connh=nothing
%>
response.write ".....................<img src='"&uuu&"' alt='jlllllllhgg'/><br />"
为什么这里从来都不能显示??? 纪录不可能没有的
向下有无数个呢!!
如果只判断一次的话!! 总说记录不纯在?????????????????????????????????????????????????????????????????????????
如何改呀??二楼??
发现大问题!!!!!!!!!!!!!!!!!是不是 where id="&ppppp&"",connh, 这里锁定了???????
哪个方法可以向下移动?? 展开
dim connh,mdbfileh,ppppp
ppppp=application("3gk")
mdbfileh=server.mappath("3gwapkj/#our_668.asp")
set connh=server.createobject("adodb.connection")
connh.open "driver={microsoft access driver (*.mdb)};uid=admin;pwd=;dbq="&mdbfileh
set rsh=server.createobject("adodb.recordset")
rsh.open "select url from urls where id="&ppppp&"",connh,3,2
if Not rsh.eof Then
iii=rsh("url")
response.write "<img src='"&iii&"' alt='jjjjjjjj'/><br />"
rsh.movenext
if not rsh.eof Then
uuu=rsh("url")
response.write ".....................<img src='"&uuu&"' alt='jlllllllhgg'/><br />"
Else
ppppp=0
end if
Else
ppppp=0
end if
rsh.close
set rsh=nothing
connh.close
set connh=nothing
%>
response.write ".....................<img src='"&uuu&"' alt='jlllllllhgg'/><br />"
为什么这里从来都不能显示??? 纪录不可能没有的
向下有无数个呢!!
如果只判断一次的话!! 总说记录不纯在?????????????????????????????????????????????????????????????????????????
如何改呀??二楼??
发现大问题!!!!!!!!!!!!!!!!!是不是 where id="&ppppp&"",connh, 这里锁定了???????
哪个方法可以向下移动?? 展开
2个回答
展开全部
补:先把判断改成一个,再修改一下语句:rsh.open "select url,id from urls where id="&ppppp&"",connh,3,2
if Not rsh.eof Then
iii=rsh("url")
response.write "<img src='"&iii&"' alt='jjjjjjjj'/><br />"
rsh.movenext
if not rsh.eof Then
uuu=rsh("url")
response.write ".....................<img src='"&uuu&"' alt='jlllllllhgg'/><br />"
Else
ppppp=0
end if
Else
ppppp=0
end if
你的判断语句不合理~~
if not rsh.eof Then 既然是一样的条件为什么要判断两次呢~~
if Not rsh.eof Then
iii=rsh("url")
response.write "<img src='"&iii&"' alt='jjjjjjjj'/><br />"
rsh.movenext
if not rsh.eof Then
uuu=rsh("url")
response.write ".....................<img src='"&uuu&"' alt='jlllllllhgg'/><br />"
Else
ppppp=0
end if
Else
ppppp=0
end if
你的判断语句不合理~~
if not rsh.eof Then 既然是一样的条件为什么要判断两次呢~~

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