这个方程组这么解
3个回答
展开全部
x^2+y^2 =1 (1)
x^2+y^2 -x+√3y =0 (2)
sub (1) into (2)
1-x+√3y =0
x=1+√3y (3)
sub (3) into (1)
(1+√3y)^2+y^2 =1
4y^2 +2√3y =0
y= 0 or -√3/2
from (3)
y=0 , x= 1
y=-√3/2 , x= -1/2
(x,y) =(1,0) or (-1/2, -√3/2)
x^2+y^2 -x+√3y =0 (2)
sub (1) into (2)
1-x+√3y =0
x=1+√3y (3)
sub (3) into (1)
(1+√3y)^2+y^2 =1
4y^2 +2√3y =0
y= 0 or -√3/2
from (3)
y=0 , x= 1
y=-√3/2 , x= -1/2
(x,y) =(1,0) or (-1/2, -√3/2)
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询