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分式方程:
1/(x+1)+1/(x²-1)+1/(1-x)
=1/(x+1)+1/(x²-1)-1/(x-1)
=(x-1)/(x²-1)+1/(x²-1)-(x+1)/(x²-1)
=[x-1+1-(x+1)]/(x²-1)
=-1/(x²-1)
=1/(1-x²)
1/(x+1)+1/(x²-1)+1/(1-x)
=1/(x+1)+1/(x²-1)-1/(x-1)
=(x-1)/(x²-1)+1/(x²-1)-(x+1)/(x²-1)
=[x-1+1-(x+1)]/(x²-1)
=-1/(x²-1)
=1/(1-x²)
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