Question

已知sin(π+α)=-1/3,求tan(α-3/2π)的值

大家写解的时候详细点，谢谢了

Answer 1

sin(π+α)=-1/3
-sina=-1/3
sina=1/桐卜3
cosa=2√2/野漏3
tan(α-3/2π)
=-cota
=-(2√2/局脊穗3)/(1/3)
=-2√2

Answer 2

sin(π+α)=-1/3
-sina=-1/3
sina=1/桐卜3
cosa=2√2/野漏3
tan(α-3/2π)
=-cota
=-(2√2/局脊穗3)/(1/3)
=-2√2