Question

我想做一个6位电子计时器,希望有大神帮我做程序

最好给个仿真图

Answer 1

#include<reg51.h>
#define uchar unsigned char
#define uint unsigned int
sbit w1=P2^2;
sbit w2=P2^3;
sbit w3=P2^4;
sbit w4=P2^5;
sbit w5=P2^6;
sbit w6=P2^7;
sbit key1=P3^4;
sbit key2=P3^5;
sbit key3=P3^6;
sbit key4=P3^7;

sbit beep=P1^0;
uchar code table[10]=
{0xFC,0x60,0xDA,0xF2,0x66,
0xB6,0xBE,0xE0,0xFE,0xF6};
uchar num,miao,fen,shi;
uchar fen1,shi1;
uchar d1,d2,d3,d4,d5,d6;
void delay(uint ms)
{
uchar x;
for(ms;ms>0;ms--)
for(x=110;x>0;x--);
}
void display()
{
d1=shi/10;
d2=shi%10;
d3=fen/10;
d4=fen%10;
d5=miao/10;
d6=miao%10;
w1=0;P0=table[d1];delay(10);
P0=0x00;w1=1;
w2=0;P0=table[d2]|0x01;delay(10);
P0=0x00;w2=1;
w3=0;P0=table[d3];delay(10);
P0=0x00;w3=1;
w4=0;P0=table[d4]|0x01;delay(10);
P0=0x00;w4=1;
w5=0;P0=table[d5];delay(10);
P0=0x00;w5=1;
w6=0;P0=table[d6];delay(10);
P0=0x00;w6=1;
}
void disp_set()
{
d1=shi1/10;
d2=shi1%10;
d3=fen1/10;
d4=fen1%10;
w1=0;P0=table[d1];delay(10);
P0=0x00;w1=1;
w2=0;P0=table[d2]|0x01;delay(10);
P0=0x00;w2=1;
w3=0;P0=table[d3];delay(10);
P0=0x00;w3=1;
w4=0;P0=table[d4]|0x01;delay(10);
P0=0x00;w4=1;
w5=0;P0=table[0];delay(10);
P0=0x00;w5=1;
w6=0;P0=table[0];delay(10);
P0=0x00;w6=1;
}
void didi()
{
uchar i;
beep=0;for(i=0;i<5;i++)display();
beep=1;for(i=0;i<5;i++)display();
}
void didi1()
{
uchar i;
beep=0;for(i=0;i<5;i++)disp_set();
beep=1;for(i=0;i<5;i++)disp_set();
}
void keyscan()
{
uchar k_flag,set_flag;
if(key1==0)
{
delay(10);
if(key1==0)
{
k_flag=1;
didi();
}
while(key1==0)display();
}
while(k_flag==1)
{
display();
if(key1==0)
{
delay(10);
if(key1==0)
{
k_flag=2;
didi();
}
while(key1==0)display();
}
if(key2==0)
{
delay(10);
if(key2==0)
{
shi++;didi();
if(shi==24)shi=0;
}
while(key2==0)display();
}
if(key3==0)
{
delay(10);
if(key3==0)
{
if(shi==0)shi=24;
shi--;didi();
}
while(key3==0)display();
}
}
while(k_flag==2)
{
display();
if(key1==0)
{
delay(10);
if(key1==0)
{
k_flag=3;
didi();
}
while(key1==0)display();
}
if(key2==0)
{
delay(10);
if(key2==0)
{
fen++;didi();
if(fen==60)fen=0;
}
while(key2==0)display();
}
if(key3==0)
{
delay(10);
if(key3==0)
{
if(fen==0)fen=60;
fen--;didi();
}
while(key3==0)display();
}
}
while(k_flag==3)
{
display();
if(key1==0)
{
delay(10);
if(key1==0)
{
didi();
didi();
k_flag=0;
}
while(key1==0)display();
}
if(key2==0)
{
delay(10);
if(key2==0)
{
didi();
miao++;
if(miao==60)miao=0;
}
while(key2==0)display();
}
if(key3==0)
{
delay(10);
if(key3==0)
{
didi();
if(miao==0)miao=60;
miao--;
}
while(key3==0)display();
}
}
if(key4==0)
{
delay(10);
if(key4==0)
{
didi1();
set_flag=1;
}
while(key4==0)disp_set();
}
while(set_flag==1)
{
disp_set();
if(key2==0)
{
delay(10);
if(key2==0)
{ didi1();
shi1++;
if(shi1==24)shi1=0;
}
while(key2==0)disp_set();
}
if(key3==0)
{
delay(10);
if(key3==0)
{ didi1();
if(shi1==0)shi1=24;
shi1--;
}
while(key3==0)disp_set();
}
if(key4==0)
{
delay(10);
if(key4==0)
{ didi1();
set_flag=2;
}
while(key4==0)disp_set();
}
}
while(set_flag==2)
{
disp_set();
if(key2==0)
{
delay(10);
if(key2==0)
{ didi1();
fen1++;
if(fen1==60)fen1=0;
}
while(key2==0)disp_set();
}
if(key3==0)
{
delay(10);
if(key3==0)
{ didi1();
if(fen1==0)fen1=60;
fen1--;
}
while(key3==0)disp_set();
}
if(key4==0)
{
delay(10);
if(key4==0)
{
didi1();
didi1();
set_flag=0;
}
while(key4==0)disp_set();
}
}
}
void b_s()
{
uchar i;
if((shi>=7)&&(shi<=20))
{
if((fen==0)&&(miao<=15))
{
beep=0;for(i=0;i<5;i++)display();
beep=1;for(i=0;i<5;i++)display();
}
}
if((shi1!=0)||(fen1!=0))
{
if((shi1==shi)&&(fen1==fen)&&(miao<=15))
{
beep=0;for(i=0;i<5;i++)display();
beep=1;for(i=0;i<5;i++)display();
}
}
}
void main()
{
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1;
TR0=1;
while(1)
{
display();
keyscan();
b_s();
}
}
void T0_time() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
num++;
if(num==20)
{
num=0;
miao++;
if(miao==60)
{
miao=0;
fen++;
if(fen==60)
{
fen=0;
shi++;
if(shi==24)shi=0;
}
}
}
}

追问

谢谢了