log9(16)·log32(18)=
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括号内是真数吧？
方法一：log a^n (b^m) =(m/n)log a (b)
log9(16)·log32(18)
=log3^2 (2^4)·log 2^5 (2*3^2)
=2log 3 (2) * [(1/5) + (2/5)log 2 (3)]
=(2/5)log 3(2) +4/5
方法二：利用换底公式log a (b) =lgb/lga
log9(16)·log32(18)
= (lg16/lg9)*(lg18/lg32)
=[4lg2/(2lg3)]*[(lg2+2lg3)/5(lg2)]
=(2/5)(lg2/lg3) +4/5
=（2/5）log 3 (2) +4/5
方法一：log a^n (b^m) =(m/n)log a (b)
log9(16)·log32(18)
=log3^2 (2^4)·log 2^5 (2*3^2)
=2log 3 (2) * [(1/5) + (2/5)log 2 (3)]
=(2/5)log 3(2) +4/5
方法二：利用换底公式log a (b) =lgb/lga
log9(16)·log32(18)
= (lg16/lg9)*(lg18/lg32)
=[4lg2/(2lg3)]*[(lg2+2lg3)/5(lg2)]
=(2/5)(lg2/lg3) +4/5
=（2/5）log 3 (2) +4/5
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