一道分数数学题求解！
[(1-1/4-5/12)^3:(1/3-1/2)^2-(3/2)^-2]:{[(-4)^-3:(1/8-3/4)-2/5]^2x(-4/3)^3}/=分号^数字=次方:...
[(1-1/4-5/12)^3:(1/3-1/2)^2-(3/2)^-2]:{[(-4)^-3:(1/8-3/4)-2/5]^2x(-4/3)^3}
/=分号 ^数字=次方 :=除 x=乘 求解啊！！ 展开
/=分号 ^数字=次方 :=除 x=乘 求解啊！！ 展开
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解：[(1-1/4-5/12)^3:(1/3-1/2)^2-(3/2)^-2]:{[(-4)^-3:(1/8-3/4)-2/5]^2x(-4/3)^3}
=[(1-1/4-5/12)^3÷(1/3-1/2)^2-(3/2)^（-2）]÷{[(-4)^(-3)÷(1/8-3/4)-2/5]^2x(-4/3)^3}
=[(1/3)^3÷(-1/6)^2-(2/3)^2]÷{[(-1/4)^3÷(-5/8)-2/5]^2x(-4/3)^3}
=[(1/27)÷(1/36)-(4/9)]÷{[(-1/64)÷(-5/8)-2/5]^2x(-64/27)}
=[(1/27)x36)-(4/9)]÷{[(-1/64)x(-8/5)-2/5]^2x(-64/27)}
=[(4/3)-(4/9)]÷{[(1/40)-2/5]^2x(-64/27)}
=[8/9]÷{[-3/8]^2x(-64/27)}
=[8/9]÷{[9/64]x(-64/27)}
=[8/9]÷{-1/3}
=-(8/9)x3
=-8/3
=-二又三分之二。
=[(1-1/4-5/12)^3÷(1/3-1/2)^2-(3/2)^（-2）]÷{[(-4)^(-3)÷(1/8-3/4)-2/5]^2x(-4/3)^3}
=[(1/3)^3÷(-1/6)^2-(2/3)^2]÷{[(-1/4)^3÷(-5/8)-2/5]^2x(-4/3)^3}
=[(1/27)÷(1/36)-(4/9)]÷{[(-1/64)÷(-5/8)-2/5]^2x(-64/27)}
=[(1/27)x36)-(4/9)]÷{[(-1/64)x(-8/5)-2/5]^2x(-64/27)}
=[(4/3)-(4/9)]÷{[(1/40)-2/5]^2x(-64/27)}
=[8/9]÷{[-3/8]^2x(-64/27)}
=[8/9]÷{[9/64]x(-64/27)}
=[8/9]÷{-1/3}
=-(8/9)x3
=-8/3
=-二又三分之二。
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