Question

sin(x)=x-x^3/3!+x^5/5!-x^7/7!+...,直到最后一项的绝对值小于10的负七次方为止。用C语言编程

Answer 1

#include<stdio.h>#include<math.h>
double jc(int n);
double sum(double x);
void main(){
double he;
scanf("%lf",&he); printf("%lf\n",sum(he));

}double jc(int n){
if (n==1)
return 1; else
return n*jc(n-1);
}
double sum(double x){
int i=1,t=0;
double sum1=0;
while(pow(x,i)/jc(i)>0.0000001){
sum1=sum1+pow(-1,t)*pow(x,i)/jc(i);

t++;
i=i+2;

}

return sum1;
}