Question

编写shell脚本,提示用户从键盘输入当天的日期，日期格式为XX/XX/XXXX，如果输入正确，则显示:

today is:xx month is:xx year is : xxxx，如果输入时间错误则显示wrong date

Answer 1

#!/bin/bash
read -p "please enter the date: " date
if [[ $date =~ "[0-9]{2}/[0-9]{2}/[0-9]{4}" ]]
then
echo "today is:${date:0:2} month is:${date:3:2} year is:${date:6:4}"
else
echo "wrong date"
fi

我没有对日期范围做校验，你可以自己加一下。