
先化简,再求代数式(1-3/x+2)/x2-1/x+2的值,其中x=4sin45°-2cos60°
1个回答
展开全部
x=4sin45°-2cos60°=2倍根号2减1
(1-3/x+2)/(x²-1)/(x+2)
=(x+2-3)/(x+2)*(x+2)/(x-1)(x+1)
=(x-1)/(x+2)*(x+2)/(x-1)(x+1)
=1/(x+1)
=1/(2√2-1+1)
=1/(2√2)
=(√2)/4
(1-3/x+2)/(x²-1)/(x+2)
=(x+2-3)/(x+2)*(x+2)/(x-1)(x+1)
=(x-1)/(x+2)*(x+2)/(x-1)(x+1)
=1/(x+1)
=1/(2√2-1+1)
=1/(2√2)
=(√2)/4
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询