Question

√(2x-x²)>x

Answer 1

√（2x-x²）＞x，
2x-x²≥0，且2x-x²＞x²，
x（x-2）≤0，且x（x-1）＜0，
0≤x≤2，且0＜x＜1，
所以0＜x＜1

Answer 2

√(2x-x^2)>x
2x-x^2 ≥0
x^2-2x ≤0
x(x-2) ≤0
0≤x≤2 (1)
√(2x-x^2)>x
2x-x^2 >x^2
x^2-x <0
x(x-1) <0
0<x<1 (2)
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√(2x-x^2)>x
(1) and (2)
0≤x≤2 and 0<x<1
=>0<x<1