Question

已知x-2y=3,则(2x+y-6)/(3x-y-9)=?

Answer 1

x-2y=3

则：x=2y+3
代入原式，原式=(4y+6+y-6)/(6y+9-y-9)
=5y/5y
=1

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Answer 2

(2x+y-6)/(3x-y-9)=(2x+y-6)/[3x-y-(x-2y+6)]=(2x+y-6)/(2x+y-6)=1

Answer 3

∵x-2y=3
∴x=3+2y
∴(2x+y-6)/(3x-y-9)
=[2﹙3+2y﹚+y-6]／[3﹙3+2y﹚-y-9]
=5y/5y
=1
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Answer 4

x-2y=3
x=2y+3
…
(2x+y-6)/(3x-y-9)
=(4y+6+y-6)/(6y-y+9-9)
=5y/5y
=1（且y不等于0）

Answer 5

(2x+y-6)/(3x-y-9)
=(2x+y-6)/[3x-y-(x-2y+6)]
=(2x+y-6)/(2x+y-6)
=1

Answer 6

解：因为：x-2y=3，则：x=3+2y
(2x+y-6)/(3x-y-9)=[2(3+2y)+y-6]/[3(3+2y)-y-9]=5y/5y=1

Answer 7

2x+y-6=(x-2y)+(x-2y)+5y-6=5y

3x-y-9=(x-2y)+(x-2y)+(x-2y)+5y+9=5y

所以(2x+y-6)/(3x-y-9)=1