Question

这个题怎么做。详细步骤

Answer 1

如图

Answer 2

let
u= e^x -1
du= e^x dx
x=0, u= 0
x=2, u= e^2 -1
∫(0->2) e^x/(e^x -1) ^(1/3) dx
=∫(0->e^2 -1) du/u^(1/3)
=(3/2)[ u^(2/3)]|(0->e^2 -1)
=(3/2) (e^2-1)^(2/3)