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高数极限问题,求解答,谢谢!
1个回答
展开全部
let
y=x-1
y->0
tan(πy/2)~ πy/2
/
lim(x->1) (2-x)^[tan(πx/2)]
=lim(y->0) (1-y)^[-1/tan(πy/2)]
=lim(y->0) (1-y)^[-2/(πy) ]
=e^(2/π)
y=x-1
y->0
tan(πy/2)~ πy/2
/
lim(x->1) (2-x)^[tan(πx/2)]
=lim(y->0) (1-y)^[-1/tan(πy/2)]
=lim(y->0) (1-y)^[-2/(πy) ]
=e^(2/π)
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