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急急急，帮帮忙

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Answer 1

#include int main(){ double total, result; scanf("%lf",&total);//输入业绩，单位万元。 switch((int)(total)/5) { case 0: if(tatal<1)//小于1万元的。 result = total*0.03; else result = total*0.1; break; case 1: case 2: case 3: result = total*0.15; break; default: if(total == 20) result = total*0.15; else result = total*0.2; break; } printf("%lf\n", result); return 0;}