求详细解题步骤（要真的很详细，因为真的不会）
2个回答
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(a)
g(x)=f(x).sinx
g'(x) = f(x).cosx + f'(x).sinx
g'(π/3)
= f(π/3).cos(π/烂帆3) + f'(π/3).sin(π/3)
=4(1/2) +(-2)(√3/2)
=2-√消备3
(b)
h(x)=cosx/f(x)
h'(x) =[-f(x).sinx - cosx.f'(x) ]/[f(x)]^2
h'(π/3)
=[-f(π/3).sin(π/3) - cos(π/3).f'(π/3) ]/[f(π/3)]^2
=[-4(√3/2) - (1/2)(-2)) ]/(-4)^2
=(-2√拿历毁3 +1 )/16
g(x)=f(x).sinx
g'(x) = f(x).cosx + f'(x).sinx
g'(π/3)
= f(π/3).cos(π/烂帆3) + f'(π/3).sin(π/3)
=4(1/2) +(-2)(√3/2)
=2-√消备3
(b)
h(x)=cosx/f(x)
h'(x) =[-f(x).sinx - cosx.f'(x) ]/[f(x)]^2
h'(π/3)
=[-f(π/3).sin(π/3) - cos(π/3).f'(π/3) ]/[f(π/3)]^2
=[-4(√3/2) - (1/2)(-2)) ]/(-4)^2
=(-2√拿历毁3 +1 )/16
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