Question

shell如何将find返回的多个结果分别赋值给变量?

如题：shell如何将find返回的多个结果分别赋值给变量？例：file = test.txtpath=find /home/test/ -name $fileif [ $path = 一个地址返回 ] thenecho $path #打印返回的结果（地址）else for path in $path (将每个地址循环赋给一个变量，如返回的结果有/home/test/a/test.txt；/home/test/b/test.txt；/home/test/b/bb/test.txt）doi=+1i = $path （将path的地址循环赋给变量）（例：1 = /home/test/a/；2 = /home/test/b/；依此类推）echo $idonefi

Answer 1

#!/bin/bash
declare path=/autorun/
declare keyfile=*.txt
result=`find $path -name $keyfile`
count=`find $path -name $keyfile|wc -l`
for((i=1;i<=$count;i++))
do
x=${i}"p"
name=`find $path -name $keyfile |sed -n "$x"`
echo 结果$i：$name
done