Question

化简(x²+xy+y²)(x²-xy+y²)=? 有过程

Answer 1

(x²+xy+y²)(x²-xy+y²)=[(x²+y²)+xy][(x²+y²)-xy]
=(x²+y²)²-(xy)²
=x^4+2x²y²+y^4-x²y²
=x^4+x²y²+y^4

祝你开心！希望能帮到你，如果不懂，请追问，祝学习进步！O(∩_∩)O

Answer 2

(x²+xy+y²)(x²-xy+y²)=[(x²+y²)+xy][(x²+y²)-xy]
=(x²+y²)²-(xy)²
=x^4+2x²y²+y^4-x²y²
=x^4+x²y²+y^4

Answer 3

(x²+xy+y²)(x²-xy+y²)
=（x²+y²）²-（xy）²
=x四次方+y四次方+（xy）²

Answer 4

x^2*x^2-x^2*xy+x^2y^2+xy*x^2-xy*xy+xy*y^2+y^2*x^2-y^2*xy+y^2*y^2
=x^4-x^3y+x^2y^2+x^3y-x^2y^2+xy^3+x^2y^2-xy^3+y^4
=x^4+x^2y^2+y^4

Answer 5

先将它分成这样，{（x²+y²）-xy}{（x²+y²）+xy}，然后将其平方差公式化出来，然后再讲平方化出来，之后合并一下同类项就好了。

不能全写过程，电脑上不太好写，只能口头说说了，抱歉啊。

谢谢。