Question

谁能帮我解决下面几道分解因式的数学题？

1：（a-b）²+4ab　　2：（p-4)（p+1)+3p

3：4xy²-4x²y-y³　　　4：3ax²-3ay²

这几道是初二上期的分解因式题 这章我真心没学好 - -
这里求速度！求解答！求质量！求正确！求详细过程！回答好加分蛮！！
看不清楚题的话就问我 第三道的最后是y三次方 其他都是二次
PS： 这是人教版八年级上册数学书171页第5题！~

Answer 1

1：（a-b）²+4ab　　
展开来
a²-2ab+b²+4ab
=a²+2ab+b²
=(a+b)²

2：（p-4)（p+1)+3p
=p²-3p-4+3p
=p²-4
=(p+2)(p-2)

3：4xy²-4x²y-y³
=-y(-4xy+4x²+y²)
=-y(4x²-4xy+y²)
=-y(2x-y)²

4：3ax²-3ay²
=3a(x²-y²)
=3a(x+y)(x-y)

希望有帮到你，若果有问题欢迎追问，请记得采纳。 :)

Answer 2

1、(a-b)^2+4ab
=a^2+b^2-2ab+4ab
=a^2+b^2+2ab
=(a*a+a*b)+(a*b+b*b)
=a*(a+b)+b*(a+b)
=(a+b)*(a+b)
2、(p-4)*(p+1)+3p
=p^2-3p-4+3p
=p*p-4
=p*p+(p*2-p*2)-4
=p(p+2)-2(p+2)
=(p-2)(p+2)
3、4xy^2-4x^2y-y^3
=y(4xy-4x*x-y*y)
=-y(4x^2-4xy+y^2)
=-y[(4x*x-2xy)+(y*y-2xy)]
=-y[2x(2x-y)+y(y-2x)]
=-y[2x(2x-y)-y(2x-y)]
=-y(2x-y)(2x-y)
4、3ax^2-3ay^2
=3a(x*x-y*y)
=3a[x*x+(x*y-x*y)-y*y]
=3a[(x*x+x*y)-(x*y+y*y)]
=3a[x(x+y)-y(x+y)]
=3a(x+y)(x-y)

Answer 3

1：（a-b）²+4ab　　
=a²+b²-2ab+4ab
=a²+b²+2ab
=（a+b）²

2：（p-4)（p+1)+3p
=p²+p-4p-4+3p
=p²-4
=p²-2²
=(p+2)(p-2)

3：4xy²-4x²y-y³　 提公因式先
=y(4xy-4x²-y²)
=﹣y(-4xy+4x²+y²)
=﹣y(2x-y)²
　　

4：3ax²-3ay² 提公因式先
=3a(x²-y² )
=3a(x+y)(x-y)

Answer 4

1 。=a²-2ab+b²+4ab 分解
=a²+2ab+b²=(a+b)²
2：（p-4)（p+1)+3p 分解再合并
=p²+p-4p-4+3p
=p²-4
=p²-2²
=(p+2)(p-2)

3：4xy²-4x²y-y³　 提公因式先
=y(4xy-4x²-y²)
=﹣y(-4xy+4x²+y²)
=﹣y(2x-y)²
　　

4：3ax²-3ay² 提公因式先
=3a(x²-y² )
=3a(x+y)(x-y)

Answer 5

1.(a-b)²+4ab
=（a-b）×（a-b）+4ab
=a(a-b)-b(a-b)+4ab
=(a²-ab)-(ab-b²)+4ab
=a²-ab-ab+b²+4ab
=a²-2ab+b²+4ab
=a²+2ab+b²
=a²+ab+ab+b²
=a(a+b)+b(a+b)
=(a+b)×(a+b)
=(a+b)²

Answer 6

1.=a²-2ab+b²+4ab=　a²+2ab+b²　=（a+b）²;
2=p²-3p-4+3p=p²-4=(p+2)(p-2)
3=-y(4x²-4xy+y²)=-y(2x-y)²
4=3a(x²-y²)=3a(x+y)(x-y)