Question

在标况下，5.6L氢气和6.72L氯气的混合气体充分反应所得混合气体若用2.50mol.L的NAOH溶液完全吸收.

1》需要NAOH的体积为多少毫升？2》所得溶液中NACLO的物质的量

Answer 1

n(H2)=5.6/22.4=0.25mol n(Cl2)=6.72/22.4=0.3mol
H2 + Cl2 ===========2HCl
1mol 1mol 2mol
0.25mol x=0.25mol y=0.5mol
HCl + NaOH =====NaCl + H2O
1mol 1mol
0.5mol x=0.5mol
Cl2 + 2NaOH ====NaCl + NaClO + H2O
1mol 2mol 1mol
0.3-0.25=0.05mol x=0.1mol y=0.05mol
n(NaOH)共=0.1+0.5=0.6mol
需要NAOH的体积为: V=0.6/2.5=0.24L=240ml

所得溶液中NACLO的物质的量0.05mol

Answer 2

根据H2+Cl2=2HCl
n（HCl）=2×5.6/22.4=0.5mol
根据Cl2+2NaOH=NaCl + NaClO + H2O
n（NaClO）=（6.72-5.6）/22.4=0.05mol
n（NaOH）=0.5+0.05×2=0.6mol
c（NaOH）=1000×0.6/2.5=240ml