
3个回答
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我喜欢变量代换
令x=1+t
t=x-1,dt=dx
-1<=t<=1
0<=x<=2
原积分
=(1/4)∫[0,2](x-1)x^4 dx
=(1/4)∫[0,2]x^5-x^4 dx
=(1/4)[x^6/6-x^5/5] [0,2]
=(1/4){[2^6/6-2^5/5]-[0-0]}
=(1/4)[32/3-32/5]
=(32/4)[1/3-1/5]
=8*2/15
=16/15
令x=1+t
t=x-1,dt=dx
-1<=t<=1
0<=x<=2
原积分
=(1/4)∫[0,2](x-1)x^4 dx
=(1/4)∫[0,2]x^5-x^4 dx
=(1/4)[x^6/6-x^5/5] [0,2]
=(1/4){[2^6/6-2^5/5]-[0-0]}
=(1/4)[32/3-32/5]
=(32/4)[1/3-1/5]
=8*2/15
=16/15
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