Question

计算，能减算的要减算。2分之1÷5分之4＋(9分之2＋8分之3)

2分之1÷[13分之6×(4分之3＋3分之1)] (6分之1＋4分之1－3分之1)÷24分之1 [1－(4分之1＋8分之3)]÷16分之9 谢谢，不要光答，要做出来。

Answer 1

2分之1÷[13分之6×(4分之3＋3分之1)]=1/2÷[6/13×(9/12+4/12)]=1/2÷[6/13 ×13/12]=1/2÷1/2=1 (6分之1＋4分之1－3分之1)÷24分之1 =(2/12+3/12-4/12)÷1/24=1/12÷1/24=1/12×24=2 [1－(4分之1＋8分之3)]÷16分之9=[1-(2/8+3/8)]÷ 9/16=[1-5/8]÷9/16=3/8÷9/16=3/8×16/9=2/3

Answer 2

宋德福

Answer 3

(1/2) / (4/5) + ( 2/9 + 3/8 )
= (5/10) / (8/10) + ( 16/72 + 27/72 )
= 5/8 + 43/72
= 45/72 + 43/72
= 88/72
= 11/9
= 1+ 2/9

(1/2) / [ 6/13 X (3/4 + 1/3) ]
= (1/2) / [ 6/13 X 3/4 + 6/13 X 1/3 ]
= (1/2) / [ 18/52 + 2/13 ]
= (1/2) / [ 9/26 + 4/26 ]
= (1/2) / [ 13/26 ]
= (1/2) / [ 1/2 ]
= 1

( 1/6 + 1/4 - 1/3 ) / (1/24)
= ( 1/6 + 1/4 - 1/3 ) X 24
= 24/6 + 24/4 - 24/3
= 4 + 6 - 8
= 2

[ 1 - (1/4 + 3/8) ] / (9/16)
= [ 1 - (2/8 + 3/8) ] / (9/16)
= [ 1 - 5/8 ] / (9/16)
= (3/8) / (9/16)
= (6/16) / (9/16)
= 6/9
= 2/3