x平方-6x+9分之1+9-x平方分之x+2x+6分之1
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1/(x²-6x+9)+x/(9-x²)+1/(2x+6)
=1/(x-3)²-x/[(x+3)(x-3)]+1/[2(x+3)]
=[2(x+3)-2x(x-3)+(x-3)²]/[2(x-3)²(x+3)]
=(-x²+2x+15)/[2(x-3)²(x+3)]
=-(x+3)(x-5)/[2(x-3)²(x+3)]
=(5-x)/[2(x-3)²]
=(5-x)/(2x²-12x+18)
=1/(x-3)²-x/[(x+3)(x-3)]+1/[2(x+3)]
=[2(x+3)-2x(x-3)+(x-3)²]/[2(x-3)²(x+3)]
=(-x²+2x+15)/[2(x-3)²(x+3)]
=-(x+3)(x-5)/[2(x-3)²(x+3)]
=(5-x)/[2(x-3)²]
=(5-x)/(2x²-12x+18)
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