能简算的要用简便方法计算①3.28×0.46+6.72×0.46?
1个回答
展开全部
解题思路:①、②利用小数乘法分配律的逆运算,
③、④按小数四则混合运算的顺序计算,先算乘除后算加减,
⑤、⑥按小数四则混合运算的顺序计算,先算乘除后算加减,有括号的先算括号里面的,
①3.28×0.46+6.72×0.46,
=(3.28+6.72)×0.46,
=10×0.46,
=4.6,
②9.73×2.8-4.73×2.8,
=(9.73-4.73)×2.8,
=5×2.8,
=14,
③1.35×6.2+5.79÷0.3,
=8.37+19.3,
=27.67,
④27.9+3.6×2.5÷0.48,
=27.9+18.75,
=46.65,
⑤0.6×(5.3-1.7)÷0.9,
=0.6×3.6÷0.9,
=2.4,
⑥6.4÷[(4.3+2.1)÷0.8],
=6.4÷6.4×0.8,
=1×0.8,
=0.8.
,1,能简算的要用简便方法计算
①3.28×0.46+6.72×0.46
②9.73×2.8-4.73×2.8
③1.35×6.2+5.79÷0.3
④27.9+3.6×2.5÷0.48
⑤0.6×(5.3-1.7)÷0.9
⑥6.4÷[(4.3+2.1)÷0.8].
③、④按小数四则混合运算的顺序计算,先算乘除后算加减,
⑤、⑥按小数四则混合运算的顺序计算,先算乘除后算加减,有括号的先算括号里面的,
①3.28×0.46+6.72×0.46,
=(3.28+6.72)×0.46,
=10×0.46,
=4.6,
②9.73×2.8-4.73×2.8,
=(9.73-4.73)×2.8,
=5×2.8,
=14,
③1.35×6.2+5.79÷0.3,
=8.37+19.3,
=27.67,
④27.9+3.6×2.5÷0.48,
=27.9+18.75,
=46.65,
⑤0.6×(5.3-1.7)÷0.9,
=0.6×3.6÷0.9,
=2.4,
⑥6.4÷[(4.3+2.1)÷0.8],
=6.4÷6.4×0.8,
=1×0.8,
=0.8.
,1,能简算的要用简便方法计算
①3.28×0.46+6.72×0.46
②9.73×2.8-4.73×2.8
③1.35×6.2+5.79÷0.3
④27.9+3.6×2.5÷0.48
⑤0.6×(5.3-1.7)÷0.9
⑥6.4÷[(4.3+2.1)÷0.8].
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
北京埃德思远电气技术咨询有限公司
2021-11-22 广告
2021-11-22 广告
假设条件在短路的实际计算中, 为了能在准确范围内迅速地计算短路电流, 通常采取以下简化假设。(1)不考虑发电机的摇摆现象。(2)不考虑磁路饱和,认为短路回路各元件的电抗为常数。(3)不考虑线路对地电容, 变压器的磁支路和高压电网中的电阻, ...
点击进入详情页
本回答由北京埃德思远电气技术咨询有限公司提供
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询