Question

初一一道数学题

（x-y+x-y分之4xy）（x+y-x+y分之4xy)

Answer 1

解：原式={[(x-y)²+4xy]/(x-y)}{[(x+y)²-4xy]/(x+y)}
=[(x+y)²/(x-y)][(x-y)²/(x+y)]
=(x+y)(x-y)
=x²-y²

Answer 2

楼主，您好！
您的式子没有等号，是要化简吗？您们初一就学分式啊，啧啧...
1 解：原式=2x-y-4xy/y
2 解：原式=y+4xy/y
希望对您有帮助，祝您学业进步！

Answer 3

完全平方公式 前面 X-Y看成a
后面x-y分之4xy看成b
原式=（a+b）（a-b）

Answer 4

解：原式={[(x-y)²+4xy]/(x-y)}{[(x+y)²-4xy]/(x+y)}
=[(x+y)²/(x-y)][(x-y)²/(x+y)]
=(x+y)(x-y)