Question

C语言题：输入一行字符，分别统计出其中的英文字母、空格、数字和其它字符。

Answer 1

#include<stdio.h>
#include<conio.h>
main()
{
int zimu=0,dight=0,space=0,other=0,i=0;
char c;
printf("Input string:");
while((c=getchar())!='\n') yj
{
if('A'<=c&&c<='Z'||'a'<=c&&c<='z')
++zimu;
else if ((c<='9')&&(c>='0'))
++dight;
else if (c==' ')
++space;
else
++other;
}
printf("zimu:%d\ndight:%d\nspace:%d\nother:%d\n",zimu,dight,space,other);
getch();
}

我用的软件是devcpp-4.9.9.2
还有一种是

#include<stdio.h>
#include<conio.h>
main()
{
int zimu=0,dight=0,space=0,other=0,i=0;
char *p,s[1000];
printf("Input string:");
while((s[i]=getchar())!='\n') i++;
p=&s[0];/*p=s;*/
while(*p!='\n')
{
if('A'<=*p&&*p<='Z'||'a'<=*p&&*p<='z')
++zimu;
else if ((*p<='9')&&(*p>='0'))
++dight;
else if (*p==' ')
++space;
else
++other;
p++;
}
printf("zimu:%d\ndight:%d\nspace:%d\nother:%d\n",zimu,dight,space,other);
getch();
}