(3/4a^4b^7+1/2a^3b^8-1/9a^2b^6)/(-1/3ab^3)^2,其中a=1/2，b=-4
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解：(3/4a^4b^7+1/2a^3b^8-1/9a^2b^6)/(-1/3ab^3)^2
=(3/4a^4b^7+1/2a^3b^8-1/9a^2b^6)/(1/9a^2b^6)
={(3/4a^4b^7)/(1/9a^2b^6)}+{(1/2a^3b^8)/(1/9a^2b^6)}-{(1/9a^2b^6)/(1/9a^2b^6)}
=3/4×9a^2b+1/2×9ab^2-1
将a=1/2，b=-4带入上述等式得
=3/4×9(1/2)^2×(-4)+1/2×9×(1/2)×(-4)^2-1
=-27/4+36-1
=113/4
=(3/4a^4b^7+1/2a^3b^8-1/9a^2b^6)/(1/9a^2b^6)
={(3/4a^4b^7)/(1/9a^2b^6)}+{(1/2a^3b^8)/(1/9a^2b^6)}-{(1/9a^2b^6)/(1/9a^2b^6)}
=3/4×9a^2b+1/2×9ab^2-1
将a=1/2，b=-4带入上述等式得
=3/4×9(1/2)^2×(-4)+1/2×9×(1/2)×(-4)^2-1
=-27/4+36-1
=113/4
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