因式分解-x^3+2x^2y-xy^2和16(x-y)^2-9(x+y)^2和(x+2)(x+4)+x^2-4
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-x^3+2x^2y-xy^2
=-x(x²-2xy+y²)
=-x(x-y)²
16(x-y)^2-9(x+y)^2
=[4(x-y)]²-[3(x+y)]²
=(4x-4y)²-(3x+3y)²
=[4x-4y-(3x+3y)][4x-4y+(3x+3y)]
=(x-7y)(7x-y)
(x+2)(x+4)+x^2-4
=(x+2)(x+4)+(x-2)(x+2)
=(x+2)[(x+4)+(x-2)]
=(x+2)(2x+2)
=2(x+2)(x+1)
=-x(x²-2xy+y²)
=-x(x-y)²
16(x-y)^2-9(x+y)^2
=[4(x-y)]²-[3(x+y)]²
=(4x-4y)²-(3x+3y)²
=[4x-4y-(3x+3y)][4x-4y+(3x+3y)]
=(x-7y)(7x-y)
(x+2)(x+4)+x^2-4
=(x+2)(x+4)+(x-2)(x+2)
=(x+2)[(x+4)+(x-2)]
=(x+2)(2x+2)
=2(x+2)(x+1)
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