Question

求解数学题：x-2- (2-x/2)= (x-2/3) (3x+2/4)-(5x+1/2)=2 要过程 详细点 急急急！！！~

这里是两道题

Answer 1

解：1) 原式可分解为x-2-2+x/2=x-2/3 再等式两边成6去掉分母可得6x-12-12+3x=6x-4 即x=20/3 2) 原式可分解为3x+1/2-5x-1/2=2 化简的3x-5x=2 即x=-1

Answer 2

x-2- (2-x/2)= (x-2/3)
去括号得
x-2-2+x/2=x-2/3
x+x/2-x=4-2/3
x/2=10/3
x=20/3

(3x+2/4)-(5x+1/2)=2
3x+1/2-5x-1/2=2
-2x=2
x=-1

Answer 3

x-2- (2-x/2)= (x-2/3)
x-2-2+x/2=x-2/3
x/2=4-2/3
x=2*(10/3)=20/3

(3x+2/4)-(5x+1/2)=2
3x+1/2-5x-1/2=2
-2x=2
x=-1

Answer 4

x-2- (2-x/2)= (x-2/3)
6(x-2)-3(2-x)=2(x-2)
6x-12-6+3x=2x-4
7x=14
x=2

(3x+2/4)-(5x+1/2)=2
3x+2-10x-2=8
-7x=8
x=-8/7