设x=-2又1/2求6x+(x/x-2-x/x+2)/4x/x^4-2x^3+8x-16
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设x=-2又1/2
6x+(x/x-2-x/x+2)/4x/x^4-2x^3+8x-16
=6x+x（1/x-2 -1/x+2）*(x^4-2x³+8x-16)/4x
=6x+x（(x+2-x+2)/(x-2)(x+2)）*(x^3(x-2)+8(x-2))/4x
=6x+（4x/(x-2)(x+2)）*((x^3+8)(x-2)/4x)
=6x+（4x/(x-2)(x+2)）*((x+2)(x^2-2x+4)(x-2)/4x)
=6x+x^2-2x+4
=x^2+4x+4
=(x+2)^2
=(-5/2+2)^2
=1/4
6x+(x/x-2-x/x+2)/4x/x^4-2x^3+8x-16
=6x+x（1/x-2 -1/x+2）*(x^4-2x³+8x-16)/4x
=6x+x（(x+2-x+2)/(x-2)(x+2)）*(x^3(x-2)+8(x-2))/4x
=6x+（4x/(x-2)(x+2)）*((x^3+8)(x-2)/4x)
=6x+（4x/(x-2)(x+2)）*((x+2)(x^2-2x+4)(x-2)/4x)
=6x+x^2-2x+4
=x^2+4x+4
=(x+2)^2
=(-5/2+2)^2
=1/4
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